Base | Representation |
---|---|
bin | 11000100101100010… |
… | …001101110001100000 |
3 | 2112010211101002011100 |
4 | 120211202031301200 |
5 | 413031234430310 |
6 | 20043333314400 |
7 | 1623130206000 |
oct | 304542156140 |
9 | 75124332140 |
10 | 26399530080 |
11 | 10217934760 |
12 | 5149195a00 |
13 | 264947c121 |
14 | 13c61b6000 |
15 | a479c2ec0 |
hex | 62588dc60 |
26399530080 has 1152 divisors, whose sum is σ = 118313395200. Its totient is φ = 5310627840.
The previous prime is 26399530049. The next prime is 26399530121. The reversal of 26399530080 is 8003599362.
26399530080 is a `hidden beast` number, since 2 + 6 + 39 + 9 + 530 + 0 + 80 = 666.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 233624104 + ... + 233624216.
It is an arithmetic number, because the mean of its divisors is an integer number (102702600).
Almost surely, 226399530080 is an apocalyptic number.
26399530080 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 26399530080, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (59156697600).
26399530080 is an abundant number, since it is smaller than the sum of its proper divisors (91913865120).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
26399530080 is a wasteful number, since it uses less digits than its factorization.
26399530080 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 209 (or 184 counting only the distinct ones).
The product of its (nonzero) digits is 349920, while the sum is 45.
The spelling of 26399530080 in words is "twenty-six billion, three hundred ninety-nine million, five hundred thirty thousand, eighty".
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