Base | Representation |
---|---|
bin | 100110011011001010000… |
… | …100101111101100110010 |
3 | 100100102120222220021022111 |
4 | 212123022010233230302 |
5 | 321230221020130310 |
6 | 5341010134155534 |
7 | 361525025022133 |
oct | 46331204575462 |
9 | 10312528807274 |
10 | 2640500161330 |
11 | 928914559a99 |
12 | 3678b61b2baa |
13 | 161cc8a84785 |
14 | 91b2d8d9c8a |
15 | 48a436cd28a |
hex | 266ca12fb32 |
2640500161330 has 8 divisors (see below), whose sum is σ = 4752900290412. Its totient is φ = 1056200064528.
The previous prime is 2640500161241. The next prime is 2640500161363. The reversal of 2640500161330 is 331610050462.
2640500161330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 2639185446249 + 1314715081 = 1624557^2 + 36259^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×26405001613302 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2640500161292 and 2640500161301.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132025008057 + ... + 132025008076.
Almost surely, 22640500161330 is an apocalyptic number.
2640500161330 is a deficient number, since it is larger than the sum of its proper divisors (2112400129082).
2640500161330 is a wasteful number, since it uses less digits than its factorization.
2640500161330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 264050016140.
The product of its (nonzero) digits is 12960, while the sum is 31.
The spelling of 2640500161330 in words is "two trillion, six hundred forty billion, five hundred million, one hundred sixty-one thousand, three hundred thirty".
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