Base | Representation |
---|---|
bin | 1100000000011111111110… |
… | …11011011110011000100011 |
3 | 10110111100002011111122102102 |
4 | 12000033333123132120203 |
5 | 11430111330014022211 |
6 | 132054255044041015 |
7 | 5363505436156544 |
oct | 600177733363043 |
9 | 113440064448372 |
10 | 26405449360931 |
11 | 8460540859363 |
12 | 2b6567769316b |
13 | 119703bc45594 |
14 | 67405dc444cb |
15 | 30bcedd32a3b |
hex | 1803ff6de623 |
26405449360931 has 2 divisors, whose sum is σ = 26405449360932. Its totient is φ = 26405449360930.
The previous prime is 26405449360909. The next prime is 26405449360937. The reversal of 26405449360931 is 13906394450462.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 26405449360931 - 222 = 26405445166627 is a prime.
It is a super-2 number, since 2×264054493609312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (26405449360937) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13202724680465 + 13202724680466.
It is an arithmetic number, because the mean of its divisors is an integer number (13202724680466).
Almost surely, 226405449360931 is an apocalyptic number.
26405449360931 is a deficient number, since it is larger than the sum of its proper divisors (1).
26405449360931 is an equidigital number, since it uses as much as digits as its factorization.
26405449360931 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16796160, while the sum is 56.
The spelling of 26405449360931 in words is "twenty-six trillion, four hundred five billion, four hundred forty-nine million, three hundred sixty thousand, nine hundred thirty-one".
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