Base | Representation |
---|---|
bin | 100110011100000001101… |
… | …000000101001110111011 |
3 | 100100111222221122021211212 |
4 | 212130001220011032323 |
5 | 321234123113441301 |
6 | 5341242430313335 |
7 | 361560103000613 |
oct | 46340150051673 |
9 | 10314887567755 |
10 | 2641432171451 |
11 | 929252664a97 |
12 | 367b1635884b |
13 | 162116ba8058 |
14 | 91bbb5c9a43 |
15 | 48a9a42e4bb |
hex | 26701a053bb |
2641432171451 has 2 divisors, whose sum is σ = 2641432171452. Its totient is φ = 2641432171450.
The previous prime is 2641432171373. The next prime is 2641432171457. The reversal of 2641432171451 is 1541712341462.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2641432171451 - 230 = 2640358429627 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2641432171399 and 2641432171408.
It is not a weakly prime, because it can be changed into another prime (2641432171457) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1320716085725 + 1320716085726.
It is an arithmetic number, because the mean of its divisors is an integer number (1320716085726).
Almost surely, 22641432171451 is an apocalyptic number.
2641432171451 is a deficient number, since it is larger than the sum of its proper divisors (1).
2641432171451 is an equidigital number, since it uses as much as digits as its factorization.
2641432171451 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 161280, while the sum is 41.
The spelling of 2641432171451 in words is "two trillion, six hundred forty-one billion, four hundred thirty-two million, one hundred seventy-one thousand, four hundred fifty-one".
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