Base | Representation |
---|---|
bin | 11000100110110101… |
… | …110100000111101001 |
3 | 2112012100121110220122 |
4 | 120212311310013221 |
5 | 413102342220342 |
6 | 20045435133025 |
7 | 1623514402115 |
oct | 304665640751 |
9 | 75170543818 |
10 | 26421445097 |
11 | 10229242843 |
12 | 51545a4175 |
13 | 2650b830a8 |
14 | 13c907c745 |
15 | a498a14d2 |
hex | 626d741e9 |
26421445097 has 2 divisors, whose sum is σ = 26421445098. Its totient is φ = 26421445096.
The previous prime is 26421445093. The next prime is 26421445139. The reversal of 26421445097 is 79054412462.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 26079343081 + 342102016 = 161491^2 + 18496^2 .
It is a cyclic number.
It is not a de Polignac number, because 26421445097 - 22 = 26421445093 is a prime.
It is a super-3 number, since 3×264214450973 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (26421445091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13210722548 + 13210722549.
It is an arithmetic number, because the mean of its divisors is an integer number (13210722549).
Almost surely, 226421445097 is an apocalyptic number.
It is an amenable number.
26421445097 is a deficient number, since it is larger than the sum of its proper divisors (1).
26421445097 is an equidigital number, since it uses as much as digits as its factorization.
26421445097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 483840, while the sum is 44.
The spelling of 26421445097 in words is "twenty-six billion, four hundred twenty-one million, four hundred forty-five thousand, ninety-seven".
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