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26421625193 is a prime number
BaseRepresentation
bin11000100110110110…
…100000000101101001
32112012100221121221212
4120212312200011221
5413102414001233
620045443042505
71623516052145
oct304666400551
975170847855
1026421625193
1110229356087
125154670435
132650c17062
1413c90c8225
15a498d9a48
hex626da0169

26421625193 has 2 divisors, whose sum is σ = 26421625194. Its totient is φ = 26421625192.

The previous prime is 26421625163. The next prime is 26421625201. The reversal of 26421625193 is 39152612462.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25916814169 + 504811024 = 160987^2 + 22468^2 .

It is a cyclic number.

It is not a de Polignac number, because 26421625193 - 214 = 26421608809 is a prime.

It is a super-3 number, since 3×264216251933 (a number of 32 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 26421625193.

It is not a weakly prime, because it can be changed into another prime (26421625103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13210812596 + 13210812597.

It is an arithmetic number, because the mean of its divisors is an integer number (13210812597).

Almost surely, 226421625193 is an apocalyptic number.

It is an amenable number.

26421625193 is a deficient number, since it is larger than the sum of its proper divisors (1).

26421625193 is an equidigital number, since it uses as much as digits as its factorization.

26421625193 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 155520, while the sum is 41.

The spelling of 26421625193 in words is "twenty-six billion, four hundred twenty-one million, six hundred twenty-five thousand, one hundred ninety-three".