Base | Representation |
---|---|
bin | 111100000110101010001100… |
… | …110101110011011011111011 |
3 | 1021122221200211101012212000111 |
4 | 330012222030311303123323 |
5 | 234121423140022123141 |
6 | 2334112151302245151 |
7 | 106451652014560342 |
oct | 7406521465633373 |
9 | 1248850741185014 |
10 | 264340420114171 |
11 | 772551628a5355 |
12 | 25792b3ba267b7 |
13 | b46626b87b8cb |
14 | 493c204ac8b59 |
15 | 208617aacb381 |
hex | f06a8cd736fb |
264340420114171 has 2 divisors, whose sum is σ = 264340420114172. Its totient is φ = 264340420114170.
The previous prime is 264340420114103. The next prime is 264340420114223. The reversal of 264340420114171 is 171411024043462.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 264340420114171 - 215 = 264340420081403 is a prime.
It is a super-2 number, since 2×2643404201141712 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (264340420111171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 132170210057085 + 132170210057086.
It is an arithmetic number, because the mean of its divisors is an integer number (132170210057086).
Almost surely, 2264340420114171 is an apocalyptic number.
264340420114171 is a deficient number, since it is larger than the sum of its proper divisors (1).
264340420114171 is an equidigital number, since it uses as much as digits as its factorization.
264340420114171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129024, while the sum is 40.
The spelling of 264340420114171 in words is "two hundred sixty-four trillion, three hundred forty billion, four hundred twenty million, one hundred fourteen thousand, one hundred seventy-one".
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