Base | Representation |
---|---|
bin | 1100000001100001001010… |
… | …01010000010111000010011 |
3 | 10110121200101212110011101221 |
4 | 12000300211022002320103 |
5 | 11431200011132030103 |
6 | 132122323231105511 |
7 | 5366154542223313 |
oct | 600604512027023 |
9 | 113550355404357 |
10 | 26440442064403 |
11 | 8474368276404 |
12 | 2b70402672297 |
13 | 119a4277b3093 |
14 | 675a1d3b1443 |
15 | 30cb9ae211bd |
hex | 180c25282e13 |
26440442064403 has 2 divisors, whose sum is σ = 26440442064404. Its totient is φ = 26440442064402.
The previous prime is 26440442064299. The next prime is 26440442064469. The reversal of 26440442064403 is 30446024404462.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 26440442064403 - 221 = 26440439967251 is a prime.
It is a super-2 number, since 2×264404420644032 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 26440442064403.
It is not a weakly prime, because it can be changed into another prime (26440442064203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13220221032201 + 13220221032202.
It is an arithmetic number, because the mean of its divisors is an integer number (13220221032202).
Almost surely, 226440442064403 is an apocalyptic number.
26440442064403 is a deficient number, since it is larger than the sum of its proper divisors (1).
26440442064403 is an equidigital number, since it uses as much as digits as its factorization.
26440442064403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1769472, while the sum is 43.
Adding to 26440442064403 its reverse (30446024404462), we get a palindrome (56886466468865).
The spelling of 26440442064403 in words is "twenty-six trillion, four hundred forty billion, four hundred forty-two million, sixty-four thousand, four hundred three".
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