Search a number
-
+
264853 = 833191
BaseRepresentation
bin1000000101010010101
3111110022101
41000222111
531433403
65402101
72152111
oct1005225
9443271
10264853
11170a96
12109331
1393724
146c741
155371d
hex40a95

264853 has 4 divisors (see below), whose sum is σ = 268128. Its totient is φ = 261580.

The previous prime is 264839. The next prime is 264871. The reversal of 264853 is 358462.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 264853 - 213 = 256661 is a prime.

It is a super-2 number, since 2×2648532 = 140294223218, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (264893) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1513 + ... + 1678.

It is an arithmetic number, because the mean of its divisors is an integer number (67032).

2264853 is an apocalyptic number.

It is an amenable number.

264853 is a deficient number, since it is larger than the sum of its proper divisors (3275).

264853 is an equidigital number, since it uses as much as digits as its factorization.

264853 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3274.

The product of its digits is 5760, while the sum is 28.

The square root of 264853 is about 514.6387082216. The cubic root of 264853 is about 64.2197039056.

It can be divided in two parts, 2648 and 53, that added together give a triangular number (2701 = T73).

The spelling of 264853 in words is "two hundred sixty-four thousand, eight hundred fifty-three".

Divisors: 1 83 3191 264853