Base | Representation |
---|---|
bin | 11000101110000110… |
… | …101101001100011001 |
3 | 2112111211221001012012 |
4 | 120232012231030121 |
5 | 413330042014224 |
6 | 20105511155305 |
7 | 1626524305124 |
oct | 305606551431 |
9 | 75454831165 |
10 | 26543313689 |
11 | 10291010492 |
12 | 5189375b35 |
13 | 26701b2699 |
14 | 13db3233bb |
15 | a5542580e |
hex | 62e1ad319 |
26543313689 has 2 divisors, whose sum is σ = 26543313690. Its totient is φ = 26543313688.
The previous prime is 26543313677. The next prime is 26543313733. The reversal of 26543313689 is 98631334562.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 26416976089 + 126337600 = 162533^2 + 11240^2 .
It is a cyclic number.
It is not a de Polignac number, because 26543313689 - 212 = 26543309593 is a prime.
It is not a weakly prime, because it can be changed into another prime (26543313659) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13271656844 + 13271656845.
It is an arithmetic number, because the mean of its divisors is an integer number (13271656845).
Almost surely, 226543313689 is an apocalyptic number.
It is an amenable number.
26543313689 is a deficient number, since it is larger than the sum of its proper divisors (1).
26543313689 is an equidigital number, since it uses as much as digits as its factorization.
26543313689 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2799360, while the sum is 50.
The spelling of 26543313689 in words is "twenty-six billion, five hundred forty-three million, three hundred thirteen thousand, six hundred eighty-nine".
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