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265436131 is a prime number
BaseRepresentation
bin11111101001000…
…11101111100011
3200111110112220211
433310203233203
51020422424011
642201114551
76402112162
oct1764435743
9614415824
10265436131
11126917104
1274a88a57
1342cb86cc
14273773d9
1518482b21
hexfd23be3

265436131 has 2 divisors, whose sum is σ = 265436132. Its totient is φ = 265436130.

The previous prime is 265436107. The next prime is 265436141. The reversal of 265436131 is 131634562.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-265436131 is a prime.

It is a super-2 number, since 2×2654361312 = 140912679280498322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 265436093 and 265436102.

It is not a weakly prime, because it can be changed into another prime (265436141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 132718065 + 132718066.

It is an arithmetic number, because the mean of its divisors is an integer number (132718066).

Almost surely, 2265436131 is an apocalyptic number.

265436131 is a deficient number, since it is larger than the sum of its proper divisors (1).

265436131 is an equidigital number, since it uses as much as digits as its factorization.

265436131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12960, while the sum is 31.

The square root of 265436131 is about 16292.2107462431. The cubic root of 265436131 is about 642.6680053415.

The spelling of 265436131 in words is "two hundred sixty-five million, four hundred thirty-six thousand, one hundred thirty-one".