Base | Representation |
---|---|
bin | 111100011111011100110100… |
… | …001001011111110110101110 |
3 | 1021212222120011011112020210012 |
4 | 330133130310021133312232 |
5 | 234332331140213334014 |
6 | 2341454535251013222 |
7 | 110016022114653353 |
oct | 7437346411376656 |
9 | 1255876134466705 |
10 | 266044034121134 |
11 | 77851706564855 |
12 | 25a0914889a212 |
13 | b55aac9c59b29 |
14 | 499a8583d062a |
15 | 20b5638826c3e |
hex | f1f73425fdae |
266044034121134 has 8 divisors (see below), whose sum is σ = 403017200203608. Its totient is φ = 131704967386600.
The previous prime is 266044034121101. The next prime is 266044034121163. The reversal of 266044034121134 is 431121430440662.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×2660440341211343 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 266044034121091 and 266044034121100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 658524836732 + ... + 658524837135.
It is an arithmetic number, because the mean of its divisors is an integer number (50377150025451).
Almost surely, 2266044034121134 is an apocalyptic number.
266044034121134 is a deficient number, since it is larger than the sum of its proper divisors (136973166082474).
266044034121134 is a wasteful number, since it uses less digits than its factorization.
266044034121134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1317049673970.
The product of its (nonzero) digits is 331776, while the sum is 41.
Adding to 266044034121134 its reverse (431121430440662), we get a palindrome (697165464561796).
The spelling of 266044034121134 in words is "two hundred sixty-six trillion, forty-four billion, thirty-four million, one hundred twenty-one thousand, one hundred thirty-four".
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