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26682728057 = 131203684947
BaseRepresentation
bin11000110110011010…
…100001111001111001
32112212120021000202022
4120312122201321321
5414121234244212
620131411244225
71633136306036
oct306632417171
975776230668
1026682728057
1110352782577
125207ba9675
1326930462ab
141411a5438d
15a627b3772
hex6366a1e79

26682728057 has 4 divisors (see below), whose sum is σ = 26886413136. Its totient is φ = 26479042980.

The previous prime is 26682727969. The next prime is 26682728089. The reversal of 26682728057 is 75082728662.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 26682728057 - 218 = 26682465913 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (26682728557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101842343 + ... + 101842604.

It is an arithmetic number, because the mean of its divisors is an integer number (6721603284).

Almost surely, 226682728057 is an apocalyptic number.

It is an amenable number.

26682728057 is a deficient number, since it is larger than the sum of its proper divisors (203685079).

26682728057 is a wasteful number, since it uses less digits than its factorization.

26682728057 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 203685078.

The product of its (nonzero) digits is 4515840, while the sum is 53.

The spelling of 26682728057 in words is "twenty-six billion, six hundred eighty-two million, seven hundred twenty-eight thousand, fifty-seven".

Divisors: 1 131 203684947 26682728057