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26746834055 = 55349366811
BaseRepresentation
bin11000111010001111…
…000100110010000111
32120001000212221122112
4120322033010302013
5414234142142210
620142021251235
71634545224014
oct307217046207
976030787575
1026746834055
1110385988337
125225563b1b
1326a3400136
14141a38070b
15a68227d05
hex63a3c4c87

26746834055 has 4 divisors (see below), whose sum is σ = 32096200872. Its totient is φ = 21397467240.

The previous prime is 26746834027. The next prime is 26746834123. The reversal of 26746834055 is 55043864762.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 26746834055 - 222 = 26742639751 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 26746833994 and 26746834012.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2674683401 + ... + 2674683410.

It is an arithmetic number, because the mean of its divisors is an integer number (8024050218).

Almost surely, 226746834055 is an apocalyptic number.

26746834055 is a deficient number, since it is larger than the sum of its proper divisors (5349366817).

26746834055 is an equidigital number, since it uses as much as digits as its factorization.

26746834055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5349366816.

The product of its (nonzero) digits is 4838400, while the sum is 50.

The spelling of 26746834055 in words is "twenty-six billion, seven hundred forty-six million, eight hundred thirty-four thousand, fifty-five".

Divisors: 1 5 5349366811 26746834055