Base | Representation |
---|---|
bin | 1001111111000100… |
… | …0111000101000001 |
3 | 20220210202001001112 |
4 | 2133301013011001 |
5 | 20442143421033 |
6 | 1121551213105 |
7 | 123265314044 |
oct | 23761070501 |
9 | 6823661045 |
10 | 2680451393 |
11 | 1156054894 |
12 | 629817195 |
13 | 339430919 |
14 | 1b5dc4c5b |
15 | 10a4c2c48 |
hex | 9fc47141 |
2680451393 has 2 divisors, whose sum is σ = 2680451394. Its totient is φ = 2680451392.
The previous prime is 2680451377. The next prime is 2680451401. The reversal of 2680451393 is 3931540862.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1570695424 + 1109755969 = 39632^2 + 33313^2 .
It is a cyclic number.
It is not a de Polignac number, because 2680451393 - 24 = 2680451377 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2680451393.
It is not a weakly prime, because it can be changed into another prime (2680451093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1340225696 + 1340225697.
It is an arithmetic number, because the mean of its divisors is an integer number (1340225697).
Almost surely, 22680451393 is an apocalyptic number.
It is an amenable number.
2680451393 is a deficient number, since it is larger than the sum of its proper divisors (1).
2680451393 is an equidigital number, since it uses as much as digits as its factorization.
2680451393 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 155520, while the sum is 41.
The square root of 2680451393 is about 51773.0759468664. The cubic root of 2680451393 is about 1389.1078921016.
The spelling of 2680451393 in words is "two billion, six hundred eighty million, four hundred fifty-one thousand, three hundred ninety-three".
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