Base | Representation |
---|---|
bin | 100111000000100110000… |
… | …111011011011101000101 |
3 | 100111021100112020122012201 |
4 | 213000212013123131011 |
5 | 322410032430334443 |
6 | 5411255100314501 |
7 | 364450136112265 |
oct | 47004607333505 |
9 | 10437315218181 |
10 | 2680699074373 |
11 | 943972818381 |
12 | 373654842a31 |
13 | 165a34100658 |
14 | 93a646857a5 |
15 | 49ae78a734d |
hex | 270261db745 |
2680699074373 has 16 divisors (see below), whose sum is σ = 2890799452800. Its totient is φ = 2477507800320.
The previous prime is 2680699074371. The next prime is 2680699074397. The reversal of 2680699074373 is 3734709960862.
It is not a de Polignac number, because 2680699074373 - 21 = 2680699074371 is a prime.
It is a super-3 number, since 3×26806990743733 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2680699074371) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12929040 + ... + 13134742.
It is an arithmetic number, because the mean of its divisors is an integer number (180674965800).
Almost surely, 22680699074373 is an apocalyptic number.
It is an amenable number.
2680699074373 is a deficient number, since it is larger than the sum of its proper divisors (210100378427).
2680699074373 is a wasteful number, since it uses less digits than its factorization.
2680699074373 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 222492.
The product of its (nonzero) digits is 82301184, while the sum is 64.
The spelling of 2680699074373 in words is "two trillion, six hundred eighty billion, six hundred ninety-nine million, seventy-four thousand, three hundred seventy-three".
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