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2680707901537 = 19991341024463
BaseRepresentation
bin100111000000100110101…
…001000110100001100001
3100111021101010212002210201
4213000212221012201201
5322410042210322122
65411300013425201
7364450304125411
oct47004651064141
910437333762721
102680707901537
119439777a7356
1237365779b201
13165a35ba1423
1493a65902641
1549ae854ca27
hex27026a46861

2680707901537 has 4 divisors (see below), whose sum is σ = 2682048928000. Its totient is φ = 2679366875076.

The previous prime is 2680707901523. The next prime is 2680707901549. The reversal of 2680707901537 is 7351097070862.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2680707901537 - 235 = 2646348163169 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2680707961537) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 670510233 + ... + 670514230.

It is an arithmetic number, because the mean of its divisors is an integer number (670512232000).

Almost surely, 22680707901537 is an apocalyptic number.

It is an amenable number.

2680707901537 is a deficient number, since it is larger than the sum of its proper divisors (1341026463).

2680707901537 is a wasteful number, since it uses less digits than its factorization.

2680707901537 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1341026462.

The product of its (nonzero) digits is 4445280, while the sum is 55.

The spelling of 2680707901537 in words is "two trillion, six hundred eighty billion, seven hundred seven million, nine hundred one thousand, five hundred thirty-seven".

Divisors: 1 1999 1341024463 2680707901537