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2680749410593 is a prime number
BaseRepresentation
bin100111000000101001000…
…111011100100100100001
3100111021111000221222112011
4213000221013130210201
5322410133322114333
65411304055232521
7364451320010152
oct47005107344441
910437430858464
102680749410593
11943999178761
12373669678741
13165a41675ab7
1493a6b229929
1549aebeeb9cd
hex270291dc921

2680749410593 has 2 divisors, whose sum is σ = 2680749410594. Its totient is φ = 2680749410592.

The previous prime is 2680749410587. The next prime is 2680749410639. The reversal of 2680749410593 is 3950149470862.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2679742808064 + 1006602529 = 1636992^2 + 31727^2 .

It is a cyclic number.

It is not a de Polignac number, because 2680749410593 - 241 = 481726155041 is a prime.

It is a super-2 number, since 2×26807494105932 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2680749410513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1340374705296 + 1340374705297.

It is an arithmetic number, because the mean of its divisors is an integer number (1340374705297).

It is a 1-persistent number, because it is pandigital, but 2⋅2680749410593 = 5361498821186 is not.

Almost surely, 22680749410593 is an apocalyptic number.

It is an amenable number.

2680749410593 is a deficient number, since it is larger than the sum of its proper divisors (1).

2680749410593 is an equidigital number, since it uses as much as digits as its factorization.

2680749410593 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13063680, while the sum is 58.

The spelling of 2680749410593 in words is "two trillion, six hundred eighty billion, seven hundred forty-nine million, four hundred ten thousand, five hundred ninety-three".