Base | Representation |
---|---|
bin | 1111100111101011100… |
… | …0010000110001011111 |
3 | 221122122202000010220100 |
4 | 3321322320100301133 |
5 | 13344034440311341 |
6 | 323140021552143 |
7 | 25246644316134 |
oct | 3717270206137 |
9 | 848582003810 |
10 | 268349541471 |
11 | a3896358360 |
12 | 44011875653 |
13 | 1c3c7844a3b |
14 | cdb982a58b |
15 | 6ea8c1a3b6 |
hex | 3e7ae10c5f |
268349541471 has 48 divisors (see below), whose sum is σ = 429934482432. Its totient is φ = 159914606400.
The previous prime is 268349541469. The next prime is 268349541503. The reversal of 268349541471 is 174145943862.
268349541471 is a `hidden beast` number, since 2 + 6 + 8 + 3 + 495 + 4 + 147 + 1 = 666.
It is not a de Polignac number, because 268349541471 - 21 = 268349541469 is a prime.
It is a super-3 number, since 3×2683495414713 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (268349548471) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 23322906 + ... + 23334408.
It is an arithmetic number, because the mean of its divisors is an integer number (8956968384).
Almost surely, 2268349541471 is an apocalyptic number.
268349541471 is a deficient number, since it is larger than the sum of its proper divisors (161584940961).
268349541471 is a wasteful number, since it uses less digits than its factorization.
268349541471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15444 (or 15441 counting only the distinct ones).
The product of its digits is 5806080, while the sum is 54.
The spelling of 268349541471 in words is "two hundred sixty-eight billion, three hundred forty-nine million, five hundred forty-one thousand, four hundred seventy-one".
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