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2689117153 is a prime number
BaseRepresentation
bin1010000001001000…
…1010101111100001
320221102001022020121
42200102022233201
521001403222103
61122501040241
7123432055462
oct24022125741
96842038217
102689117153
11115aa33578
126306b6081
1333b1760a8
141b71dcd69
1510b1356bd
hexa048abe1

2689117153 has 2 divisors, whose sum is σ = 2689117154. Its totient is φ = 2689117152.

The previous prime is 2689117121. The next prime is 2689117157. The reversal of 2689117153 is 3517119862.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1563648849 + 1125468304 = 39543^2 + 33548^2 .

It is a cyclic number.

It is not a de Polignac number, because 2689117153 - 25 = 2689117121 is a prime.

It is not a weakly prime, because it can be changed into another prime (2689117157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1344558576 + 1344558577.

It is an arithmetic number, because the mean of its divisors is an integer number (1344558577).

Almost surely, 22689117153 is an apocalyptic number.

It is an amenable number.

2689117153 is a deficient number, since it is larger than the sum of its proper divisors (1).

2689117153 is an equidigital number, since it uses as much as digits as its factorization.

2689117153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 90720, while the sum is 43.

The square root of 2689117153 is about 51856.6982462247. The cubic root of 2689117153 is about 1390.6032529818.

It can be divided in two parts, 26891 and 17153, that added together give a palindrome (44044).

The spelling of 2689117153 in words is "two billion, six hundred eighty-nine million, one hundred seventeen thousand, one hundred fifty-three".