Base | Representation |
---|---|
bin | 11001000101011001… |
… | …011111101100111011 |
3 | 2120112002021210222200 |
4 | 121011121133230323 |
5 | 420130113141011 |
6 | 20212351321243 |
7 | 1642311126000 |
oct | 310531375473 |
9 | 76462253880 |
10 | 26934115131 |
11 | 10471673390 |
12 | 5278220223 |
13 | 2703153141 |
14 | 14371b18a7 |
15 | a798bd856 |
hex | 64565fb3b |
26934115131 has 96 divisors (see below), whose sum is σ = 50309875200. Its totient is φ = 13761316800.
The previous prime is 26934115127. The next prime is 26934115141. The reversal of 26934115131 is 13151143962.
26934115131 is a `hidden beast` number, since 26 + 93 + 411 + 5 + 131 = 666.
It is not a de Polignac number, because 26934115131 - 22 = 26934115127 is a prime.
It is a super-3 number, since 3×269341151313 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (26934115141) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 2064876 + ... + 2077878.
It is an arithmetic number, because the mean of its divisors is an integer number (524061200).
Almost surely, 226934115131 is an apocalyptic number.
26934115131 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
26934115131 is a deficient number, since it is larger than the sum of its proper divisors (23375760069).
26934115131 is a wasteful number, since it uses less digits than its factorization.
26934115131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13102 (or 13085 counting only the distinct ones).
The product of its digits is 19440, while the sum is 36.
The spelling of 26934115131 in words is "twenty-six billion, nine hundred thirty-four million, one hundred fifteen thousand, one hundred thirty-one".
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