Base | Representation |
---|---|
bin | 111110000110010101001011… |
… | …011001010100000110101011 |
3 | 1022211000102211002022200202212 |
4 | 332012111023121110012223 |
5 | 241244144322204444431 |
6 | 2404510451224515335 |
7 | 111345555021025625 |
oct | 7606251331240653 |
9 | 1284012732280685 |
10 | 273113940312491 |
11 | 7a027a76271363 |
12 | 2676b38a01bb4b |
13 | b9516c3446415 |
14 | 4b62adc9bdc15 |
15 | 21894c12a672b |
hex | f8654b6541ab |
273113940312491 has 2 divisors, whose sum is σ = 273113940312492. Its totient is φ = 273113940312490.
The previous prime is 273113940312407. The next prime is 273113940312503. The reversal of 273113940312491 is 194213049311372.
273113940312491 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-273113940312491 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (273113940312991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 136556970156245 + 136556970156246.
It is an arithmetic number, because the mean of its divisors is an integer number (136556970156246).
Almost surely, 2273113940312491 is an apocalyptic number.
273113940312491 is a deficient number, since it is larger than the sum of its proper divisors (1).
273113940312491 is an equidigital number, since it uses as much as digits as its factorization.
273113940312491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 979776, while the sum is 50.
The spelling of 273113940312491 in words is "two hundred seventy-three trillion, one hundred thirteen billion, nine hundred forty million, three hundred twelve thousand, four hundred ninety-one".
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