Base | Representation |
---|---|
bin | 1100011011110010001101… |
… | …10101010011110010100011 |
3 | 10120210221221012201000212012 |
4 | 12031321012311103302203 |
5 | 12040441330221424042 |
6 | 134053102232223135 |
7 | 5521314536540201 |
oct | 615710665236243 |
9 | 116727835630765 |
10 | 27342950186147 |
11 | 8792097607192 |
12 | 30972b683aaab |
13 | 1234576a8329b |
14 | 6a7597920071 |
15 | 3263bd72ee82 |
hex | 18de46d53ca3 |
27342950186147 has 2 divisors, whose sum is σ = 27342950186148. Its totient is φ = 27342950186146.
The previous prime is 27342950186089. The next prime is 27342950186231. The reversal of 27342950186147 is 74168105924372.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-27342950186147 is a prime.
It is not a weakly prime, because it can be changed into another prime (27342950116147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13671475093073 + 13671475093074.
It is an arithmetic number, because the mean of its divisors is an integer number (13671475093074).
It is a 1-persistent number, because it is pandigital, but 2⋅27342950186147 = 54685900372294 is not.
Almost surely, 227342950186147 is an apocalyptic number.
27342950186147 is a deficient number, since it is larger than the sum of its proper divisors (1).
27342950186147 is an equidigital number, since it uses as much as digits as its factorization.
27342950186147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20321280, while the sum is 59.
The spelling of 27342950186147 in words is "twenty-seven trillion, three hundred forty-two billion, nine hundred fifty million, one hundred eighty-six thousand, one hundred forty-seven".
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