Base | Representation |
---|---|
bin | 1100101111010001110001… |
… | …11011000100001000110011 |
3 | 10200011222202102210220002211 |
4 | 12113220320323010020303 |
5 | 12132430033304241201 |
6 | 135324512110552551 |
7 | 5620565414555152 |
oct | 627507073041063 |
9 | 120158672726084 |
10 | 28012731712051 |
11 | 8a20150840a49 |
12 | 318507b208757 |
13 | 1282787803108 |
14 | 6cbb75789599 |
15 | 338a1e905651 |
hex | 197a38ec4233 |
28012731712051 has 2 divisors, whose sum is σ = 28012731712052. Its totient is φ = 28012731712050.
The previous prime is 28012731711983. The next prime is 28012731712109. The reversal of 28012731712051 is 15021713721082.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-28012731712051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 28012731711995 and 28012731712013.
It is not a weakly prime, because it can be changed into another prime (28012731712351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14006365856025 + 14006365856026.
It is an arithmetic number, because the mean of its divisors is an integer number (14006365856026).
Almost surely, 228012731712051 is an apocalyptic number.
28012731712051 is a deficient number, since it is larger than the sum of its proper divisors (1).
28012731712051 is an equidigital number, since it uses as much as digits as its factorization.
28012731712051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 47040, while the sum is 40.
The spelling of 28012731712051 in words is "twenty-eight trillion, twelve billion, seven hundred thirty-one million, seven hundred twelve thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •