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28025000000503 = 112547727272773
BaseRepresentation
bin1100101111101000101000…
…01010110111101111110111
310200020011102102202112000121
412113310110022313233313
512133130200000004003
6135334301322552411
75621511424364032
oct627642412675767
9120204372675017
1028025000000503
118a25376987710
123187523968707
1312839914116ac
146cc5bac84019
15338edb9bdcbd
hex197d142b7bf7

28025000000503 has 4 divisors (see below), whose sum is σ = 30572727273288. Its totient is φ = 25477272727720.

The previous prime is 28025000000497. The next prime is 28025000000593. The reversal of 28025000000503 is 30500000052082.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 28025000000503 - 241 = 25825976744951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (28025000000593) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1273863636376 + ... + 1273863636397.

It is an arithmetic number, because the mean of its divisors is an integer number (7643181818322).

Almost surely, 228025000000503 is an apocalyptic number.

28025000000503 is a deficient number, since it is larger than the sum of its proper divisors (2547727272785).

28025000000503 is a wasteful number, since it uses less digits than its factorization.

28025000000503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2547727272784.

The product of its (nonzero) digits is 2400, while the sum is 25.

Adding to 28025000000503 its reverse (30500000052082), we get a palindrome (58525000052585).

The spelling of 28025000000503 in words is "twenty-eight trillion, twenty-five billion, five hundred three", and thus it is an aban number.

Divisors: 1 11 2547727272773 28025000000503