Base | Representation |
---|---|
bin | 1100101111101101011000… |
… | …01010010110010010010011 |
3 | 10200020102000011000221002121 |
4 | 12113312230022112102103 |
5 | 12133200410300002100 |
6 | 135335402334155111 |
7 | 5621631550126510 |
oct | 627665412262223 |
9 | 120212004027077 |
10 | 28027550000275 |
11 | 8a26465331241 |
12 | 3187b15952a97 |
13 | 1283ca97c90b7 |
14 | 6cc77d7cc307 |
15 | 3390da7c451a |
hex | 197dac296493 |
28027550000275 has 24 divisors (see below), whose sum is σ = 40104664081664. Its totient is φ = 19032300237600.
The previous prime is 28027550000267. The next prime is 28027550000363. The reversal of 28027550000275 is 57200005572082.
It is not a de Polignac number, because 28027550000275 - 23 = 28027550000267 is a prime.
It is a super-3 number, since 3×280275500002753 (a number of 41 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 777445221 + ... + 777481270.
Almost surely, 228027550000275 is an apocalyptic number.
28027550000275 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
28027550000275 is a deficient number, since it is larger than the sum of its proper divisors (12077114081389).
28027550000275 is a wasteful number, since it uses less digits than its factorization.
28027550000275 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1554926611 (or 1554926606 counting only the distinct ones).
The product of its (nonzero) digits is 392000, while the sum is 43.
The spelling of 28027550000275 in words is "twenty-eight trillion, twenty-seven billion, five hundred fifty million, two hundred seventy-five", and thus it is an aban number.
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