Base | Representation |
---|---|
bin | 1100110011110001000000… |
… | …11110111010111110100011 |
3 | 10200201201210111212012002121 |
4 | 12121320200132322332203 |
5 | 12142441343232111341 |
6 | 135523414104325111 |
7 | 5634665020635613 |
oct | 631704036727643 |
9 | 120651714765077 |
10 | 28166940503971 |
11 | 8a7a594670825 |
12 | 31aab37473797 |
13 | 1294192018c99 |
14 | 6d54040c0a43 |
15 | 33ca47c4e4d1 |
hex | 199e207bafa3 |
28166940503971 has 2 divisors, whose sum is σ = 28166940503972. Its totient is φ = 28166940503970.
The previous prime is 28166940503893. The next prime is 28166940504089. The reversal of 28166940503971 is 17930504966182.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 28166940503971 - 215 = 28166940471203 is a prime.
It is not a weakly prime, because it can be changed into another prime (28166940593971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14083470251985 + 14083470251986.
It is an arithmetic number, because the mean of its divisors is an integer number (14083470251986).
It is a 2-persistent number, because it is pandigital, and so is 2⋅28166940503971 = 56333881007942, but 3⋅28166940503971 = 84500821511913 is not.
Almost surely, 228166940503971 is an apocalyptic number.
28166940503971 is a deficient number, since it is larger than the sum of its proper divisors (1).
28166940503971 is an equidigital number, since it uses as much as digits as its factorization.
28166940503971 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19595520, while the sum is 61.
The spelling of 28166940503971 in words is "twenty-eight trillion, one hundred sixty-six billion, nine hundred forty million, five hundred three thousand, nine hundred seventy-one".
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