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2841489425113 = 5353613008021
BaseRepresentation
bin101001010110010101111…
…101111100001011011001
3101001122101021122202121021
4221112111331330023121
5333023332243100423
610013210123442441
7412201520413123
oct51262575741331
911048337582537
102841489425113
119a6083780769
1239a849086421
13177c4a022121
149b759132213
154dda891295d
hex29595f7c2d9

2841489425113 has 4 divisors (see below), whose sum is σ = 2895102433188. Its totient is φ = 2787876417040.

The previous prime is 2841489425083. The next prime is 2841489425123. The reversal of 2841489425113 is 3115249841482.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1898079333264 + 943410091849 = 1377708^2 + 971293^2 .

It is a cyclic number.

It is not a de Polignac number, because 2841489425113 - 25 = 2841489425081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2841489425123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26806503958 + ... + 26806504063.

It is an arithmetic number, because the mean of its divisors is an integer number (723775608297).

Almost surely, 22841489425113 is an apocalyptic number.

It is an amenable number.

2841489425113 is a deficient number, since it is larger than the sum of its proper divisors (53613008075).

2841489425113 is an equidigital number, since it uses as much as digits as its factorization.

2841489425113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53613008074.

The product of its digits is 2211840, while the sum is 52.

The spelling of 2841489425113 in words is "two trillion, eight hundred forty-one billion, four hundred eighty-nine million, four hundred twenty-five thousand, one hundred thirteen".

Divisors: 1 53 53613008021 2841489425113