Base | Representation |
---|---|
bin | 1101000010011110110000… |
… | …10110101000000110000011 |
3 | 10202112001211100221111122012 |
4 | 12201033120112220012003 |
5 | 12224232323321321401 |
6 | 140551551553403135 |
7 | 6016344120041162 |
oct | 641173026500603 |
9 | 122461740844565 |
10 | 28672536510851 |
11 | 9154a55406aa2 |
12 | 3270b1a5694ab |
13 | 12cca6862381c |
14 | 711a885cd3d9 |
15 | 34ac89cb88bb |
hex | 1a13d85a8183 |
28672536510851 has 2 divisors, whose sum is σ = 28672536510852. Its totient is φ = 28672536510850.
The previous prime is 28672536510811. The next prime is 28672536510889. The reversal of 28672536510851 is 15801563527682.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 28672536510851 - 214 = 28672536494467 is a prime.
It is a super-2 number, since 2×286725365108512 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (28672536510811) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14336268255425 + 14336268255426.
It is an arithmetic number, because the mean of its divisors is an integer number (14336268255426).
Almost surely, 228672536510851 is an apocalyptic number.
28672536510851 is a deficient number, since it is larger than the sum of its proper divisors (1).
28672536510851 is an equidigital number, since it uses as much as digits as its factorization.
28672536510851 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192000, while the sum is 59.
The spelling of 28672536510851 in words is "twenty-eight trillion, six hundred seventy-two billion, five hundred thirty-six million, five hundred ten thousand, eight hundred fifty-one".
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