Base | Representation |
---|---|
bin | 11011001000011000… |
… | …111111100110111111 |
3 | 2210012020121201110121 |
4 | 123020120333212333 |
5 | 434130220031400 |
6 | 21214415315411 |
7 | 2050625130346 |
oct | 331030774677 |
9 | 83166551417 |
10 | 29131798975 |
11 | 1139a160824 |
12 | 579021bb67 |
13 | 2993553496 |
14 | 15a5008b5d |
15 | b577ce21a |
hex | 6c863f9bf |
29131798975 has 12 divisors (see below), whose sum is σ = 36715620040. Its totient is φ = 22923381600.
The previous prime is 29131798967. The next prime is 29131798979. The reversal of 29131798975 is 57989713192.
It is not a de Polignac number, because 29131798975 - 23 = 29131798967 is a prime.
It is a super-3 number, since 3×291317989753 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (61).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (29131798979) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 9549885 + ... + 9552934.
Almost surely, 229131798975 is an apocalyptic number.
29131798975 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
29131798975 is a deficient number, since it is larger than the sum of its proper divisors (7583821065).
29131798975 is a wasteful number, since it uses less digits than its factorization.
29131798975 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19102890 (or 19102885 counting only the distinct ones).
The product of its digits is 8573040, while the sum is 61.
The spelling of 29131798975 in words is "twenty-nine billion, one hundred thirty-one million, seven hundred ninety-eight thousand, nine hundred seventy-five".
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