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29131798975 = 526119102819
BaseRepresentation
bin11011001000011000…
…111111100110111111
32210012020121201110121
4123020120333212333
5434130220031400
621214415315411
72050625130346
oct331030774677
983166551417
1029131798975
111139a160824
12579021bb67
132993553496
1415a5008b5d
15b577ce21a
hex6c863f9bf

29131798975 has 12 divisors (see below), whose sum is σ = 36715620040. Its totient is φ = 22923381600.

The previous prime is 29131798967. The next prime is 29131798979. The reversal of 29131798975 is 57989713192.

It is not a de Polignac number, because 29131798975 - 23 = 29131798967 is a prime.

It is a super-3 number, since 3×291317989753 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (61).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (29131798979) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 9549885 + ... + 9552934.

Almost surely, 229131798975 is an apocalyptic number.

29131798975 is a gapful number since it is divisible by the number (25) formed by its first and last digit.

29131798975 is a deficient number, since it is larger than the sum of its proper divisors (7583821065).

29131798975 is a wasteful number, since it uses less digits than its factorization.

29131798975 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19102890 (or 19102885 counting only the distinct ones).

The product of its digits is 8573040, while the sum is 61.

The spelling of 29131798975 in words is "twenty-nine billion, one hundred thirty-one million, seven hundred ninety-eight thousand, nine hundred seventy-five".

Divisors: 1 5 25 61 305 1525 19102819 95514095 477570475 1165271959 5826359795 29131798975