Base | Representation |
---|---|
bin | 1101010010000001010000… |
… | …10101011110100000111101 |
3 | 10211102002222000112000202120 |
4 | 12221000220111132200331 |
5 | 12312004304302101303 |
6 | 142041132045313153 |
7 | 6103045110452100 |
oct | 651005025364075 |
9 | 124362860460676 |
10 | 29206454331453 |
11 | 934042a072093 |
12 | 33384a65657b9 |
13 | 133b206713a19 |
14 | 72d8582dc737 |
15 | 359ad8466553 |
hex | 1a902855e83d |
29206454331453 has 24 divisors (see below), whose sum is σ = 45301001256000. Its totient is φ = 16688962382400.
The previous prime is 29206454331413. The next prime is 29206454331469. The reversal of 29206454331453 is 35413345460292.
It is not a de Polignac number, because 29206454331453 - 216 = 29206454265917 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 29206454331396 and 29206454331405.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (29206454331403) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3015048 + ... + 8216046.
It is an arithmetic number, because the mean of its divisors is an integer number (1887541719000).
Almost surely, 229206454331453 is an apocalyptic number.
It is an amenable number.
29206454331453 is a deficient number, since it is larger than the sum of its proper divisors (16094546924547).
29206454331453 is a wasteful number, since it uses less digits than its factorization.
29206454331453 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5239217 (or 5239210 counting only the distinct ones).
The product of its (nonzero) digits is 9331200, while the sum is 51.
The spelling of 29206454331453 in words is "twenty-nine trillion, two hundred six billion, four hundred fifty-four million, three hundred thirty-one thousand, four hundred fifty-three".
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