2932480000049 has 2 divisors, whose sum is σ = 2932480000050. Its totient is φ = 2932480000048.

The previous prime is 2932479999991. The next prime is 2932480000063. The reversal of 2932480000049 is 9400000842392.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2931406258225 + 1073741824 = 1712135^2 + 32768^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2932480000049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2932479999970 and 2932480000015.

It is not a weakly prime, because it can be changed into another prime (2932480003049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1466240000024 + 1466240000025.

It is an arithmetic number, because the mean of its divisors is an integer number (1466240000025).

Almost surely, 2^{2932480000049} is an apocalyptic number.

It is an amenable number.

2932480000049 is a deficient number, since it is larger than the sum of its proper divisors (1).

2932480000049 is an equidigital number, since it uses as much as digits as its factorization.

2932480000049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 124416, while the sum is 41.

The spelling of 2932480000049 in words is "two trillion, nine hundred thirty-two billion, four hundred eighty million, forty-nine", and thus it is an aban number.