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2973400201193 is a prime number
BaseRepresentation
bin101011010001001100011…
…101100111011111101001
3101112020212101001111020112
4223101030131213133221
5342204010422414233
610153543341304105
7424551425461202
oct53211435473751
911466771044215
102973400201193
11a47014996184
12400321865035
1318750ca31396
14a3cb02ac5a9
15525293b2048
hex2b44c7677e9

2973400201193 has 2 divisors, whose sum is σ = 2973400201194. Its totient is φ = 2973400201192.

The previous prime is 2973400201171. The next prime is 2973400201223. The reversal of 2973400201193 is 3911020043792.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2334380625424 + 639019575769 = 1527868^2 + 799387^2 .

It is a cyclic number.

It is not a de Polignac number, because 2973400201193 - 236 = 2904680724457 is a prime.

It is a super-2 number, since 2×29734002011932 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2973400201193.

It is not a weakly prime, because it can be changed into another prime (2973400201103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1486700100596 + 1486700100597.

It is an arithmetic number, because the mean of its divisors is an integer number (1486700100597).

Almost surely, 22973400201193 is an apocalyptic number.

It is an amenable number.

2973400201193 is a deficient number, since it is larger than the sum of its proper divisors (1).

2973400201193 is an equidigital number, since it uses as much as digits as its factorization.

2973400201193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81648, while the sum is 41.

The spelling of 2973400201193 in words is "two trillion, nine hundred seventy-three billion, four hundred million, two hundred one thousand, one hundred ninety-three".