Base | Representation |
---|---|
bin | 101011100011100011111… |
… | …011011010111101111000 |
3 | 101121010202202200012210100 |
4 | 223203203323122331320 |
5 | 343014403014234000 |
6 | 10211004303515400 |
7 | 426150222534000 |
oct | 53434373327570 |
9 | 11533682605710 |
10 | 2993121243000 |
11 | a54414a02839 |
12 | 4041062b8b60 |
13 | 1893336978a5 |
14 | a4c214db000 |
15 | 52cd08c8a00 |
hex | 2b8e3edaf78 |
2993121243000 has 768 divisors, whose sum is σ = 12419147520000. Its totient is φ = 648121824000.
The previous prime is 2993121242963. The next prime is 2993121243103. The reversal of 2993121243000 is 3421213992.
2993121243000 is a `hidden beast` number, since 2 + 9 + 9 + 3 + 1 + 212 + 430 + 0 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (36).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 58627485 + ... + 58678515.
It is an arithmetic number, because the mean of its divisors is an integer number (16170765000).
Almost surely, 22993121243000 is an apocalyptic number.
2993121243000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 2993121243000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (6209573760000).
2993121243000 is an abundant number, since it is smaller than the sum of its proper divisors (9426026277000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2993121243000 is a wasteful number, since it uses less digits than its factorization.
2993121243000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51098 (or 51067 counting only the distinct ones).
The product of its (nonzero) digits is 23328, while the sum is 36.
Adding to 2993121243000 its reverse (3421213992), we get a palindrome (2996542456992).
The spelling of 2993121243000 in words is "two trillion, nine hundred ninety-three billion, one hundred twenty-one million, two hundred forty-three thousand".
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