Base | Representation |
---|---|
bin | 1101100111110011010000… |
… | …00101111011001111100011 |
3 | 10221001122200212211001120121 |
4 | 12303321220011323033203 |
5 | 12411240012131244042 |
6 | 143413022313421111 |
7 | 6211111031334622 |
oct | 663715005731743 |
9 | 127048625731517 |
10 | 29954848306147 |
11 | 95a9863a47196 |
12 | 343954a10a797 |
13 | 1393964c8823b |
14 | 757b729116b9 |
15 | 36e2dadc4367 |
hex | 1b3e6817b3e3 |
29954848306147 has 2 divisors, whose sum is σ = 29954848306148. Its totient is φ = 29954848306146.
The previous prime is 29954848306133. The next prime is 29954848306181. The reversal of 29954848306147 is 74160384845992.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 29954848306147 - 211 = 29954848304099 is a prime.
It is not a weakly prime, because it can be changed into another prime (29954848306447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14977424153073 + 14977424153074.
It is an arithmetic number, because the mean of its divisors is an integer number (14977424153074).
It is a 1-persistent number, because it is pandigital, but 2⋅29954848306147 = 59909696612294 is not.
Almost surely, 229954848306147 is an apocalyptic number.
29954848306147 is a deficient number, since it is larger than the sum of its proper divisors (1).
29954848306147 is an equidigital number, since it uses as much as digits as its factorization.
29954848306147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 418037760, while the sum is 70.
The spelling of 29954848306147 in words is "twenty-nine trillion, nine hundred fifty-four billion, eight hundred forty-eight million, three hundred six thousand, one hundred forty-seven".
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