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300003431993 is a prime number
BaseRepresentation
bin1000101110110011001…
…10010001011000111001
31001200100202101101112222
410113121212101120321
514403401334310433
6345453014413425
730450236045216
oct4273146213071
91050322341488
10300003431993
1110625a130861
124a186661275
13223a0760a85
141073d796b0d
157c0cb3ab98
hex45d9991639

300003431993 has 2 divisors, whose sum is σ = 300003431994. Its totient is φ = 300003431992.

The previous prime is 300003431939. The next prime is 300003432007. The reversal of 300003431993 is 399134300003.

Together with previous prime (300003431939) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 198998964649 + 101004467344 = 446093^2 + 317812^2 .

It is a cyclic number.

It is not a de Polignac number, because 300003431993 - 212 = 300003427897 is a prime.

It is not a weakly prime, because it can be changed into another prime (300003431093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 150001715996 + 150001715997.

It is an arithmetic number, because the mean of its divisors is an integer number (150001715997).

Almost surely, 2300003431993 is an apocalyptic number.

It is an amenable number.

300003431993 is a deficient number, since it is larger than the sum of its proper divisors (1).

300003431993 is an equidigital number, since it uses as much as digits as its factorization.

300003431993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26244, while the sum is 35.

Adding to 300003431993 its reverse (399134300003), we get a palindrome (699137731996).

The spelling of 300003431993 in words is "three hundred billion, three million, four hundred thirty-one thousand, nine hundred ninety-three".