Base | Representation |
---|---|
bin | 101011101010000101110… |
… | …011010110011001001011 |
3 | 101121210212100122202002001 |
4 | 223222011303112121023 |
5 | 343123232243102103 |
6 | 10214124104451431 |
7 | 426516032160463 |
oct | 53520563263113 |
9 | 11553770582061 |
10 | 3000132003403 |
11 | a573923368a7 |
12 | 405542179b77 |
13 | 189bacc9a522 |
14 | a52c8658ba3 |
15 | 5309111b01d |
hex | 2ba85cd664b |
3000132003403 has 2 divisors, whose sum is σ = 3000132003404. Its totient is φ = 3000132003402.
The previous prime is 3000132003371. The next prime is 3000132003409. The reversal of 3000132003403 is 3043002310003.
3000132003403 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3000132003403 - 25 = 3000132003371 is a prime.
It is not a weakly prime, because it can be changed into another prime (3000132003409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1500066001701 + 1500066001702.
It is an arithmetic number, because the mean of its divisors is an integer number (1500066001702).
Almost surely, 23000132003403 is an apocalyptic number.
3000132003403 is a deficient number, since it is larger than the sum of its proper divisors (1).
3000132003403 is an equidigital number, since it uses as much as digits as its factorization.
3000132003403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 19.
Adding to 3000132003403 its reverse (3043002310003), we get a palindrome (6043134313406).
The spelling of 3000132003403 in words is "three trillion, one hundred thirty-two million, three thousand, four hundred three".
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