Base | Representation |
---|---|
bin | 1101101001001001110100… |
… | …01100110100000100010011 |
3 | 10221020002122210011010102012 |
4 | 12310210322030310010103 |
5 | 12413020202142000313 |
6 | 143450230103413135 |
7 | 6214344515612261 |
oct | 664447214640423 |
9 | 127202583133365 |
10 | 30001323000083 |
11 | 9617542778656 |
12 | 344655a4541ab |
13 | 139816056b036 |
14 | 75a100d77431 |
15 | 37060b00dda8 |
hex | 1b493a334113 |
30001323000083 has 2 divisors, whose sum is σ = 30001323000084. Its totient is φ = 30001323000082.
The previous prime is 30001323000031. The next prime is 30001323000091. The reversal of 30001323000083 is 38000032310003.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 30001323000083 - 222 = 30001318805779 is a prime.
It is not a weakly prime, because it can be changed into another prime (30001323060083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15000661500041 + 15000661500042.
It is an arithmetic number, because the mean of its divisors is an integer number (15000661500042).
Almost surely, 230001323000083 is an apocalyptic number.
30001323000083 is a deficient number, since it is larger than the sum of its proper divisors (1).
30001323000083 is an equidigital number, since it uses as much as digits as its factorization.
30001323000083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 30001323000083 its reverse (38000032310003), we get a palindrome (68001355310086).
The spelling of 30001323000083 in words is "thirty trillion, one billion, three hundred twenty-three million, eighty-three", and thus it is an aban number.
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