Base | Representation |
---|---|
bin | 1101101001001011010101… |
… | …00010100010011011111111 |
3 | 10221020011202022012021002021 |
4 | 12310211222202202123333 |
5 | 12413023332301021112 |
6 | 143450442354141011 |
7 | 6214403564165521 |
oct | 664455242423377 |
9 | 127204668167067 |
10 | 30002134001407 |
11 | 9617919542987 |
12 | 3446745b81767 |
13 | 139825c5a3489 |
14 | 75a17a967a11 |
15 | 37065730a907 |
hex | 1b496a8a26ff |
30002134001407 has 4 divisors (see below), whose sum is σ = 30066933427360. Its totient is φ = 29937334575456.
The previous prime is 30002134001393. The next prime is 30002134001423. The reversal of 30002134001407 is 70410043120003.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 30002134001407 - 223 = 30002125612799 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (30002134001447) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32399712282 + ... + 32399713207.
It is an arithmetic number, because the mean of its divisors is an integer number (7516733356840).
Almost surely, 230002134001407 is an apocalyptic number.
30002134001407 is a deficient number, since it is larger than the sum of its proper divisors (64799425953).
30002134001407 is an equidigital number, since it uses as much as digits as its factorization.
30002134001407 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 64799425952.
The product of its (nonzero) digits is 2016, while the sum is 25.
The spelling of 30002134001407 in words is "thirty trillion, two billion, one hundred thirty-four million, one thousand, four hundred seven".
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