Base | Representation |
---|---|
bin | 1101101001001011010101… |
… | …00010100010011100011001 |
3 | 10221020011202022012021010020 |
4 | 12310211222202202130121 |
5 | 12413023332301021213 |
6 | 143450442354141053 |
7 | 6214403564165556 |
oct | 664455242423431 |
9 | 127204668167106 |
10 | 30002134001433 |
11 | 9617919542a00 |
12 | 3446745b81789 |
13 | 139825c5a34a9 |
14 | 75a17a967a2d |
15 | 37065730a923 |
hex | 1b496a8a2719 |
30002134001433 has 96 divisors (see below), whose sum is σ = 48978263779200. Its totient is φ = 16243332188160.
The previous prime is 30002134001423. The next prime is 30002134001447. The reversal of 30002134001433 is 33410043120003.
It is not a de Polignac number, because 30002134001433 - 228 = 30001865565977 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (30002134001423) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 9137835 + ... + 11979327.
It is an arithmetic number, because the mean of its divisors is an integer number (510190247700).
Almost surely, 230002134001433 is an apocalyptic number.
30002134001433 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
30002134001433 is a deficient number, since it is larger than the sum of its proper divisors (18976129777767).
30002134001433 is a wasteful number, since it uses less digits than its factorization.
30002134001433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2841623 (or 2841612 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 30002134001433 its reverse (33410043120003), we get a palindrome (63412177121436).
The spelling of 30002134001433 in words is "thirty trillion, two billion, one hundred thirty-four million, one thousand, four hundred thirty-three".
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