Base | Representation |
---|---|
bin | 1101101001001100111100… |
… | …01010000110110101010001 |
3 | 10221020020222122202011102212 |
4 | 12310212132022012311101 |
5 | 12413032121000341423 |
6 | 143451104331521505 |
7 | 6214434211152212 |
oct | 664463612066521 |
9 | 127206878664385 |
10 | 30003000012113 |
11 | 961822336a607 |
12 | 3446947bb9295 |
13 | 1398369b2914b |
14 | 75a21d997409 |
15 | 3706a8371578 |
hex | 1b499e286d51 |
30003000012113 has 2 divisors, whose sum is σ = 30003000012114. Its totient is φ = 30003000012112.
The previous prime is 30003000012091. The next prime is 30003000012133. The reversal of 30003000012113 is 31121000030003.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28843269171649 + 1159730840464 = 5370593^2 + 1076908^2 .
It is a cyclic number.
It is not a de Polignac number, because 30003000012113 - 230 = 30001926270289 is a prime.
It is not a weakly prime, because it can be changed into another prime (30003000012133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15001500006056 + 15001500006057.
It is an arithmetic number, because the mean of its divisors is an integer number (15001500006057).
Almost surely, 230003000012113 is an apocalyptic number.
It is an amenable number.
30003000012113 is a deficient number, since it is larger than the sum of its proper divisors (1).
30003000012113 is an equidigital number, since it uses as much as digits as its factorization.
30003000012113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 30003000012113 its reverse (31121000030003), we get a palindrome (61124000042116).
The spelling of 30003000012113 in words is "thirty trillion, three billion, twelve thousand, one hundred thirteen".
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