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3000312300113 is a prime number
BaseRepresentation
bin101011101010010000100…
…011001000001001010001
3101121211022220220202122222
4223222100203020021101
5343124114422100423
610214154025110425
7426523351523042
oct53522043101121
911554286822588
103000312300113
11a57475091447
12405592628415
13189c0b44647b
14a530458c8c9
15530a1d823c8
hex2ba908c8251

3000312300113 has 2 divisors, whose sum is σ = 3000312300114. Its totient is φ = 3000312300112.

The previous prime is 3000312300109. The next prime is 3000312300131. The reversal of 3000312300113 is 3110032130003.

Together with next prime (3000312300131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1906848906769 + 1093463393344 = 1380887^2 + 1045688^2 .

It is a cyclic number.

It is not a de Polignac number, because 3000312300113 - 22 = 3000312300109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3000312300091 and 3000312300100.

It is not a weakly prime, because it can be changed into another prime (3000312300163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1500156150056 + 1500156150057.

It is an arithmetic number, because the mean of its divisors is an integer number (1500156150057).

Almost surely, 23000312300113 is an apocalyptic number.

It is an amenable number.

3000312300113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3000312300113 is an equidigital number, since it uses as much as digits as its factorization.

3000312300113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 3000312300113 its reverse (3110032130003), we get a palindrome (6110344430116).

The spelling of 3000312300113 in words is "three trillion, three hundred twelve million, three hundred thousand, one hundred thirteen".