Base | Representation |
---|---|
bin | 11011111100011000… |
… | …101100000011010111 |
3 | 2212110001001221022001 |
4 | 123330120230003113 |
5 | 442422024242403 |
6 | 21441140420131 |
7 | 2111346634426 |
oct | 337430540327 |
9 | 85401057261 |
10 | 30004134103 |
11 | 117a7608049 |
12 | 59943a7647 |
13 | 2aa21b1a08 |
14 | 1648c032bd |
15 | ba9193c1d |
hex | 6fc62c0d7 |
30004134103 has 2 divisors, whose sum is σ = 30004134104. Its totient is φ = 30004134102.
The previous prime is 30004134089. The next prime is 30004134137. The reversal of 30004134103 is 30143140003.
It is a weak prime.
It is an emirp because it is prime and its reverse (30143140003) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 30004134103 - 225 = 29970579671 is a prime.
It is a super-2 number, since 2×300041341032 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (30004134203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15002067051 + 15002067052.
It is an arithmetic number, because the mean of its divisors is an integer number (15002067052).
Almost surely, 230004134103 is an apocalyptic number.
30004134103 is a deficient number, since it is larger than the sum of its proper divisors (1).
30004134103 is an equidigital number, since it uses as much as digits as its factorization.
30004134103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 30004134103 its reverse (30143140003), we get a palindrome (60147274106).
The spelling of 30004134103 in words is "thirty billion, four million, one hundred thirty-four thousand, one hundred three".
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