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30004534264451 is a prime number
BaseRepresentation
bin1101101001001111110011…
…00110110100001010000011
310221020101221120201020222112
412310213321212310022003
512413043241232430301
6143451520500125535
76214520221116125
oct664477146641203
9127211846636875
1030004534264451
11961894041504a
1234470b59968ab
131398552951a76
1475a327655215
15370747dd49bb
hex1b49f99b4283

30004534264451 has 2 divisors, whose sum is σ = 30004534264452. Its totient is φ = 30004534264450.

The previous prime is 30004534264409. The next prime is 30004534264469. The reversal of 30004534264451 is 15446243540003.

It is a strong prime.

It is an emirp because it is prime and its reverse (15446243540003) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 30004534264451 - 230 = 30003460522627 is a prime.

It is a super-2 number, since 2×300045342644512 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 30004534264399 and 30004534264408.

It is not a weakly prime, because it can be changed into another prime (30004534261451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15002267132225 + 15002267132226.

It is an arithmetic number, because the mean of its divisors is an integer number (15002267132226).

Almost surely, 230004534264451 is an apocalyptic number.

30004534264451 is a deficient number, since it is larger than the sum of its proper divisors (1).

30004534264451 is an equidigital number, since it uses as much as digits as its factorization.

30004534264451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 691200, while the sum is 41.

The spelling of 30004534264451 in words is "thirty trillion, four billion, five hundred thirty-four million, two hundred sixty-four thousand, four hundred fifty-one".