Base | Representation |
---|---|
bin | 100010000111001011001101… |
… | …1110111010011000010101111 |
3 | 1110100101211002010202221212002 |
4 | 1010032112123313103002233 |
5 | 303312033202224332010 |
6 | 2542054332241002515 |
7 | 120126065054446502 |
oct | 10416263367230257 |
9 | 1410354063687762 |
10 | 300053325230255 |
11 | 8767399a79a253 |
12 | 297a041762343b |
13 | cb56ba404babc |
14 | 5414930a2d139 |
15 | 24a51200dc1a5 |
hex | 110e59bdd30af |
300053325230255 has 16 divisors (see below), whose sum is σ = 367244940518400. Its totient is φ = 235299079660320.
The previous prime is 300053325230249. The next prime is 300053325230261. The reversal of 300053325230255 is 552032523350003.
It is an interprime number because it is at equal distance from previous prime (300053325230249) and next prime (300053325230261).
It is a de Polignac number, because none of the positive numbers 2k-300053325230255 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2732422331 + ... + 2732532140.
It is an arithmetic number, because the mean of its divisors is an integer number (22952808782400).
Almost surely, 2300053325230255 is an apocalyptic number.
300053325230255 is a deficient number, since it is larger than the sum of its proper divisors (67191615288145).
300053325230255 is a wasteful number, since it uses less digits than its factorization.
300053325230255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5464954694.
The product of its (nonzero) digits is 405000, while the sum is 38.
Adding to 300053325230255 its reverse (552032523350003), we get a palindrome (852085848580258).
The spelling of 300053325230255 in words is "three hundred trillion, fifty-three billion, three hundred twenty-five million, two hundred thirty thousand, two hundred fifty-five".
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