Base | Representation |
---|---|
bin | 1000101111000000011… |
… | …00000110101111100001 |
3 | 1001200122110110111101111 |
4 | 10113200030012233201 |
5 | 14404113141410103 |
6 | 345512004503321 |
7 | 30453051010243 |
oct | 4274014065741 |
9 | 1050573414344 |
10 | 300114013153 |
11 | 10630659a049 |
12 | 4a1b76aab41 |
13 | 223ba63a806 |
14 | 10750340093 |
15 | 7c176d086d |
hex | 45e0306be1 |
300114013153 has 2 divisors, whose sum is σ = 300114013154. Its totient is φ = 300114013152.
The previous prime is 300114013103. The next prime is 300114013183. The reversal of 300114013153 is 351310411003.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 198035680144 + 102078333009 = 445012^2 + 319497^2 .
It is an emirp because it is prime and its reverse (351310411003) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 300114013153 - 29 = 300114012641 is a prime.
It is not a weakly prime, because it can be changed into another prime (300114013103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 150057006576 + 150057006577.
It is an arithmetic number, because the mean of its divisors is an integer number (150057006577).
Almost surely, 2300114013153 is an apocalyptic number.
It is an amenable number.
300114013153 is a deficient number, since it is larger than the sum of its proper divisors (1).
300114013153 is an equidigital number, since it uses as much as digits as its factorization.
300114013153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 300114013153 its reverse (351310411003), we get a palindrome (651424424156).
The spelling of 300114013153 in words is "three hundred billion, one hundred fourteen million, thirteen thousand, one hundred fifty-three".
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