Search a number
-
+
300213201011323 is a prime number
BaseRepresentation
bin100010001000010101101010…
…1001101000000001001111011
31110100222002202011021010111211
41010100223111031000021323
5303322143113424330243
62542300012433503551
7120143454662250415
oct10420532515001173
91410862664233454
10300213201011323
1187725781479936
12298073b5711bb7
13cb68ca26453a2
14541c579c499b5
1524a937abddd9d
hex1110ad534027b

300213201011323 has 2 divisors, whose sum is σ = 300213201011324. Its totient is φ = 300213201011322.

The previous prime is 300213201011303. The next prime is 300213201011329. The reversal of 300213201011323 is 323110102312003.

It is a strong prime.

It is an emirp because it is prime and its reverse (323110102312003) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-300213201011323 is a prime.

It is a super-3 number, since 3×3002132010113233 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 300213201011294 and 300213201011303.

It is not a weakly prime, because it can be changed into another prime (300213201011329) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 150106600505661 + 150106600505662.

It is an arithmetic number, because the mean of its divisors is an integer number (150106600505662).

Almost surely, 2300213201011323 is an apocalyptic number.

300213201011323 is a deficient number, since it is larger than the sum of its proper divisors (1).

300213201011323 is an equidigital number, since it uses as much as digits as its factorization.

300213201011323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 300213201011323 its reverse (323110102312003), we get a palindrome (623323303323326).

The spelling of 300213201011323 in words is "three hundred trillion, two hundred thirteen billion, two hundred one million, eleven thousand, three hundred twenty-three".