Base | Representation |
---|---|
bin | 1101101100000001110101… |
… | …00011100100010000010001 |
3 | 10221120112122122100212222220 |
4 | 12312000322203210100101 |
5 | 12421130012440244213 |
6 | 144003445012451253 |
7 | 6224442602556135 |
oct | 666007243442021 |
9 | 127515578325886 |
10 | 30100113212433 |
11 | 9655428222350 |
12 | 346172b019b29 |
13 | 13a457553a2a4 |
14 | 760bd347b3c5 |
15 | 372e8de27e23 |
hex | 1b603a8e4411 |
30100113212433 has 128 divisors (see below), whose sum is σ = 48542772579840. Its totient is φ = 16381347102720.
The previous prime is 30100113212417. The next prime is 30100113212441. The reversal of 30100113212433 is 33421231100103.
It is not a de Polignac number, because 30100113212433 - 24 = 30100113212417 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (30100113212413) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 219395185 + ... + 219532337.
It is an arithmetic number, because the mean of its divisors is an integer number (379240410780).
Almost surely, 230100113212433 is an apocalyptic number.
30100113212433 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
30100113212433 is a deficient number, since it is larger than the sum of its proper divisors (18442659367407).
30100113212433 is a wasteful number, since it uses less digits than its factorization.
30100113212433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 137427.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 30100113212433 its reverse (33421231100103), we get a palindrome (63521344312536).
The spelling of 30100113212433 in words is "thirty trillion, one hundred billion, one hundred thirteen million, two hundred twelve thousand, four hundred thirty-three".
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