Base | Representation |
---|---|
bin | 1101101100011000000000… |
… | …11000000010000001100011 |
3 | 10221121200101120212120212122 |
4 | 12312030000120002001203 |
5 | 12421323410113341003 |
6 | 144013134423414455 |
7 | 6225343655650331 |
oct | 666140030020143 |
9 | 127550346776778 |
10 | 30112022012003 |
11 | 965a489452768 |
12 | 3463ab32b442b |
13 | 13a572281c659 |
14 | 761602d18b51 |
15 | 373439681238 |
hex | 1b6300602063 |
30112022012003 has 2 divisors, whose sum is σ = 30112022012004. Its totient is φ = 30112022012002.
The previous prime is 30112022011993. The next prime is 30112022012057. The reversal of 30112022012003 is 30021022021103.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-30112022012003 is a prime.
It is not a weakly prime, because it can be changed into another prime (30112822012003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15056011006001 + 15056011006002.
It is an arithmetic number, because the mean of its divisors is an integer number (15056011006002).
Almost surely, 230112022012003 is an apocalyptic number.
30112022012003 is a deficient number, since it is larger than the sum of its proper divisors (1).
30112022012003 is an equidigital number, since it uses as much as digits as its factorization.
30112022012003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 30112022012003 its reverse (30021022021103), we get a palindrome (60133044033106).
It can be divided in two parts, 3011202 and 2012003, that added together give a palindrome (5023205).
The spelling of 30112022012003 in words is "thirty trillion, one hundred twelve billion, twenty-two million, twelve thousand, three".
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