Base | Representation |
---|---|
bin | 11100000010111001… |
… | …001000101000000001 |
3 | 2212201122111021221001 |
4 | 130002321020220001 |
5 | 443133001144131 |
6 | 21500040332001 |
7 | 2114143565263 |
oct | 340271105001 |
9 | 85648437831 |
10 | 30113303041 |
11 | 118531a1308 |
12 | 5a04a74001 |
13 | 2abb9b5a13 |
14 | 16594ddb33 |
15 | bb3a5a261 |
hex | 702e48a01 |
30113303041 has 2 divisors, whose sum is σ = 30113303042. Its totient is φ = 30113303040.
The previous prime is 30113303009. The next prime is 30113303047. The reversal of 30113303041 is 14030331103.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 26567696016 + 3545607025 = 162996^2 + 59545^2 .
It is an emirp because it is prime and its reverse (14030331103) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 30113303041 - 25 = 30113303009 is a prime.
It is a super-2 number, since 2×301133030412 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (30113303047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15056651520 + 15056651521.
It is an arithmetic number, because the mean of its divisors is an integer number (15056651521).
Almost surely, 230113303041 is an apocalyptic number.
It is an amenable number.
30113303041 is a deficient number, since it is larger than the sum of its proper divisors (1).
30113303041 is an equidigital number, since it uses as much as digits as its factorization.
30113303041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 30113303041 its reverse (14030331103), we get a palindrome (44143634144).
The spelling of 30113303041 in words is "thirty billion, one hundred thirteen million, three hundred three thousand, forty-one".
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